SV#1 Unit F Concept 10- Finding all real and imaginary zeroes of a polynomial

       First you find the p's and q's then divide p/q and find the possible zeroes. right after that you use the decartes rule of sign to which how many possible zeroes you will get. Use synthetic division until you find a zero hero you keep going until your able to distribute it or you cant anymore.
      Then use the quadratic formula -b+or- the square root of b^2 -4(a)(c)/ 2(A). you will either get a perfect square or a imaginary number but you usually always get an imaginary number. You find the zeroes which are the numbers that equaled to zero in your synthetic division and quadratic formula you put and x-then your quadratic answer your suppose to get two different answers. Then the factors is the equation you reduced while doing the synthetic division and the quadratic but you dont put x- on it. Thanks for watching!!!!!!!

WSQ question Unit F Concept 10- Finding all real and imaginary zeroes of a polynomial

SP#2 Unit E Concept 7- Graphing a polynomial and identifying all key parts

       This is my own equation that i made up. what you do is you factor x^2-4x+5. You should of gotten (x-5) and (x+1) if you didn't go back and try it again and see what you did wrong. So those two points should be where it says Factored Equation. To find your End Behavior you go back to the original equation and see the x^2 only the exponent is to see if it is even or odd in this case it is even and the x to see if it is positive or negative in this case it is positive so you sing the song and it should be the first one you say which both ends go up.Then you write the limited notation since both go up the f(x) of both should be positive infinity.
      To find the x-intercepts you go back to the factored equations and you equal them to 0. You should have (5,0)M1 because there is only one of those and (-1,0)M1 because it also only has one there's no other one that is the same as that one. Then you graph it you put the 5,0 and since it is multiplicity of 1 it is going thru the graph then you put the other one -1,0 and since it is also the multiplicity of one it is also going thru. To find the y-intercept you go back to the original equation and substitute the x's to 0's and you should of gotten 5 but to put it as a y-intercept it should be (0,5) then you put that one in as well to see how low its going to go. and that's how the graph should look like.

WPP #4 Unit E Concept 3- Maximizing Area

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WPP #3 Unit E Concept 2- Path of Donuts

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SP#1 Unit E Concept 1-Graphing a quadratic and identifying all key parts

       You first write the equation of course. you equal it to zero. then subtract 12 on both sides. you find what they have in common then you take it out and try and find the third number that you are able to factor. then multiply on the other side by the number you can take out from the two numbers to make it smaller. that will be your parent function equation that's at the top right corner. then you use (h,k) to find the vertex. for the y-intercept you plug in for x to the original equation and you find the y-intercept.to find the x-axis you look at all the points you put and draw a line to the middle of it and that would be the x-axis.
      Then you put the parent function equation and you divide it after that you square root it to delete the squared  and whatever is left should be your x-intercept and if you have an i then you are going to have an imaginary number number which is pretty much nothing so you will have to have 3 points in your graph not 5 that's only if you have an imaginary number but in this cause i don't.

WPP#2 Unit A Concept 7- Profit, Revenue, Cost

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WPP#1 Unit A Concept 6- Linear Models

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