Fibonacci Haiku: The Thugest Man Alive

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SP#5 Unit J Concept 6 Partial Fraction Decomposition with repeated factors

                    The tricky part of this was when you get your answer when you decompose it since we got a zero in out matrix we dont have to put it as your answer there is no need to. make sure to add subtract and multiply right or your whole answer will be wrong. this second picture is how you can check if your decompose answer was correct if not you probably messed up on your matrx by not plugging in the numbers right in your calculator to get your rref (reduced row echolen form) hope this helped.

SP#4 Unit J Concept 5 Partial Fraction decomposition with distinct factors

                  The trickiest part is composing it because some people might think that all you got to do is distribute the factors and they only do it in ones thinking that's the answer but you have to do it in all 3 and after that combine the like terms to get the answer. For the second pick you have to be very careful when you distribute and put the like terms where they have to be. For the last pic don't be in a rush when plugging in the numbers because people usually get it wrong because they put the numbers all quick without checking or if its not that you made a mistake in the (second picture) that might of gave you the wrong answer.

SV#5 Unit J Concept 3-4: Solving three- variable systems with Gaussian Elimination and Solving non- square systems

     The trickiest part for doing matrx is the math. As in the multiplying  and adding or subtraction to get a zero on where they have to be. Also as you can see here I got 0001 but I got 00011 and that is because in the calculator I put rref as the reduced form thats why I got confused but my answer is still right. Well hope this helped thanks for watching. :D

WPP#6 Unit I Concept 3-5 : Compound Interest, Continuously compounding interest, and Investment application problem

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SV#4 Unit I Concept 2 - Graphing Logarithmic Functions

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     The trickiest part of this concept is putting it in the calculator right because parenthesis matter a lot if you forget your answer will be totally different. The y intercept is tricky too because when it comes with the log people think its a times not an exponent so they get it wrong and when they see that its an exponent they get stuck there. When that happens you have to use the natural log its in your calculator and you divide them. So at the numerator it should be the exponent and at the denominator it is the base.

SP#3 Unit I Concept 1:Graphing exponential functions and identifying x-intercept, y-intercept, asymptotes, domain, range

      You first write out what a, b, h, and k is. When you do that you find the asymptote which is y=k. you then find the x-intercept which is y=0. you add the coefficient first then you divide the first number to leave the exponent alone. in this case if you have a negative ln ( which i didnt put there sorry) it should be ln of 2 divided by ln of -8 but whenever theres a negative the calculator will tell its a imaginary number.so it will be undefined and your answer is you dont have an x-intercept.
      Then you move on to the y-intercept and that you equal x to 0. then you just use PEMDAS pretty much. When you go to your graph you plug in the asymptote which is -2 and put it as a horizontal asymptote you plug in the y-intercept you got. You go back to your key points and your third key point is always h even if you found it on your x- intercept. you look for the numbers you dont have in there and put it on the key points. to see how it will look like you put the original equation dont forget its an exponent so you put a ^ before you put the (x+1) and the put 2nd table and you will find your points then you plug them in and it should look like that.